Transport Tycoon Forums

I wanted to make a try at modelling some bridges and tunnels. However to do that I need how much the difference in height is on a sloped tile if the tile is 12,5m x 12,5m wide. Anyone who knows?

the length and height scales in TTD are not easily comparable. E.g passenger wagons are much too high for their length, or much too short for their height.

I believe the height scale even differs between houses.

I know that. The reason I ask is that I need to know the slope of a sloped tile to make a tunnel or a bridgehead.

I had the same question when I tried to code a bridge.

I'd say to keep the pixel-ratio the same -- if a flat tile is twice as many pixels across, make the height difference on a sloped tile also twice as many pixels.

Obviously, I am not an authority on this matter.

A tile height is 8 pixels high, which means something between 5 meter (height of truck) and 250 (aircraft flight level) meters in real life.

problem with tunnel entrances is that tiles are 8 pixels high, while vehicles are 12 pixels high. the game hides this fact with some magic perspective trickery.

Eddi wrote:problem with tunnel entrances is that tiles are 8 pixels high, while vehicles are 12 pixels high. the game hides this fact with some magic perspective trickery.

According to my experience, a (train) vehicle is 6 (/,|,\) or 7 (_) px high, and there´s no "magic trickery" involved (or needed) with the perspective. They just move under the tunnel portal et voilà.

regards
Michael

In my Blender models (for grass slope ao) I always use an angle of 16 degrees (steep slope), and that works out rather good after rendering.

If you want a little more background information, here's my reasoning:
In sprite 3982 you can see that the height difference is 8 px for a slope (compare middle left with middle right)

The width of half the sprite is 32 px.
The angle between level tiles and the camera (viewpoint) is 30 degrees -> sin (30) = 0.5 -> y value is half the x value.

That means that a height of 8 px (vertical) corresponds to 8/cos(30) = 9.23 px 'real' height.

So the angle = atan ( 9.23/32) = 16.1 degrees

Applied on the 12.5 m scale ( but be careful, different objects are scaled different in OTTD: a sky scraper is one tile, but a house too)
x = 12.5 * 0.5 sqrt (2) = 8.84

Then y (the height in the real world ) : y/x = 9.23/32. So y = 8.84 * 9.23 / 32 = 2.55 m.