How GRF sets could work better together
Posted: 05 Jun 2008 09:10
Our current problem is how sets could work better together and maybe even sharing rolling stock.
The big sets are currently very incompatible and each set has to provide always all rolling stock.
Current Problems we face today.
- different base cost and multipliers
- different sense of econommy
- depot offset differences
- rail offsets differences
- how to deny cross set coupling of non engine/wagon combinations
We can see this with the Engine Pool system introduced by OTTD.
Solutions:
- classes for vehicles (EU/DACH/US/AUST) You can't put together trains with different classes. (richk67)
- maybe changeing the cost multiplier to be larger? (eis_os)
- classes for different coupling systems? TGV/ICE/DEFAULT? (eis_os)
- shared economy grf (eis_os)
- use GRM to allow certain vehicles be used by foreign sets. (Michael)
Non Solutions:
- Disabling other sets. (This is not allowed usage of grf features in the sense of Developers)
- Simple allowing all sets to be put together. The base cost problem simply shows it won't work
I try to collect all possible solutions/ideas here in the first post.
The big sets are currently very incompatible and each set has to provide always all rolling stock.
Current Problems we face today.
- different base cost and multipliers
- different sense of econommy
- depot offset differences
- rail offsets differences
- how to deny cross set coupling of non engine/wagon combinations
We can see this with the Engine Pool system introduced by OTTD.
Solutions:
- classes for vehicles (EU/DACH/US/AUST) You can't put together trains with different classes. (richk67)
- maybe changeing the cost multiplier to be larger? (eis_os)
- classes for different coupling systems? TGV/ICE/DEFAULT? (eis_os)
- shared economy grf (eis_os)
- use GRM to allow certain vehicles be used by foreign sets. (Michael)
Non Solutions:
- Disabling other sets. (This is not allowed usage of grf features in the sense of Developers)
- Simple allowing all sets to be put together. The base cost problem simply shows it won't work
I try to collect all possible solutions/ideas here in the first post.